Question

A rectangular ground is 80 m long and 50 m broad. In the middle of the ground, there is a

circular tank of radius 7 metres. Find the cost of turfing the remaining portion at the rate of ₹

0.50 pe square metre.
Pls write steps and send

Answer 1

Answer:

Answer: ₹1961.5

Step-by-step explanation:

Given:- length(l) = 80m, breadth(b) = 50m

Radius of the circular tank(r) = 7m

Cost of turting 1 m^{2}m

2

= ₹0.5

Method:- Area Of the Rectangular Ground = l × b

= 80 × 50 = 4000 m^{2}m

2

Area Of the Circular Tank = 2\piπ r²

= 2 × \frac{22}{7}

7

22

× (7)² = \frac{11}{7}

7

11

× 49 = 11 × 7 = 77 m^{2}m

2

Area Of remaining Portion = (4000 - 77) m^{2}m

2

= 3923 m^{2}m

2

∴ Cost of Painting 3923 m^{2}m

2

= ₹0.5 × 3923 m^{2}m

2

= ₹1961.5

Hence, Answer = ₹1961.5

Answer 2

Answer:

₹212

Step-by-step explanation:

Area of rectangle = l×b

80×50 = 4000m²

Area of circle = πr²

22/7×7×7 = 22×7 bcoz 7 will cut from another 7 then the remaining numbers are 22×7 = 154m²

Then we'll minus the area of circle from area of rectangle

Remaining area = 260-154 = 106m²

For finding the cost we'll divide remaining area and the cost that is given

Cost = 106/0.50 = ₹212

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