Question

A rectangular hall 16 m long and 8 m wide is to be tiled with square tiles of side
2 m each. How many tiles would be required?​

Answer 1

Answer:

l=16,b=8 , area = l×b = 16×8 =128

how many 2m tiles can be fit into area 128.square.m

128=t×2

t=64 tiles .

Answer 2

Answer:

• Number of tiles required is 32.

Step-by-step explanation:

Given that:

• A rectangular hall is 16 m long and 8 m wide.
• It is to be tiled with squares tiles of side 2 m.

To Find:

• Number of square tiles required.

Formulas Used:

• Area of a rectangle = (L × B) sq. units
• Area of a square = (S²) sq. units

Where,

• L = Length of the rectangle
• B = Breadth of the rectangle
• S = Side of the square

Solution:

Finding area of the rectangular hall:

As we know that:

Area of rectangle is (Length × Breadth) sq. units

Substituting the values,

↪ (16 × 8) m²

Multiplying the numbers,

↪ 128 m²

Hence, area of the hall is 128 m².

Finding area of a square tile:

As we know that,

Area of square is (side²) sq. units.

Substituting the values,

↪ (2²) m²

Multiplying 2 by itself 2 times,

↪ (2 × 2) m²

Opening the bracket,

↪ 4 m²

Now,

Number of tiles required is:

$\sf{\hookrightarrow\dfrac{Area\;of\;the\;hall}{Area\;of\;a\;tile}}$

Substituting the values,

$\sf{\hookrightarrow\dfrac{128}{4}}$

Dividing 128 by 4,

$\sf\hookrightarrow 32$

Hence, number of tiles required is 32.