Physics, asked by pchahat19, 3 months ago

 A rectangular hall 20 m long and 15 m broad is surrounded by a path of uniform width of 2.5m. Find the area of the path(in sq. m). ​

Answers

Answered by loverboy0001
2

αɳรωεɾ

➡️Tʜᴇ ʜᴀʟʟ ɪs Sᴜʀʀᴏᴜɴᴅᴇᴅ ʙʏ ᴠᴇʀᴀɴᴅᴀʜ 

➡️Sᴏ, Aᴅᴅɪᴛɪᴏɴᴀʟ ɪɴᴄʀᴇᴀsᴇ ɪɴ ʟᴇɴɢᴛʜ ᴡɪʟʟ ʙᴇ =2∗2.5=5

➡️Sɪᴍɪʟᴀʀʟʏ , Aᴅᴅɪᴛɪᴏɴᴀʟ ɪɴᴄʀᴇᴀsᴇ ɪɴ ᴡɪᴅᴛʜ ᴡɪʟʟ ʙᴇ =2∗2.5=5

➡️Sᴏ Aʀᴇᴀ ᴏғ Hᴀʟʟ + Vᴇʀᴀɴᴅᴀʜ =(20+5)(15+5)=25∗20=500

➡️ᴀɴᴅ Aʀᴇᴀ ᴏғ Hᴀʟʟ =20∗15=300

➡️Aʀᴇᴀ ᴏғ ᴠᴇʀᴀɴᴅᴀʜ =500−300=200 

➡️Rᴀᴛᴇ ᴏғ 1 sϙ ᴍᴇᴛʀᴇ =17.5

➡️Rᴀᴛᴇ ᴏғ 200 sϙ ᴍᴇᴛʀᴇ 17.50∗200=3500

Answered by XxinstaprincessxX
1

Explanation:

Since, The hall is Surrounded by verandah

So, Additional increase in length will be =2∗2.5=5

Similarly , Additional increase in width will be =2∗2.5=5

So Area of Hall + Verandah =(20+5)(15+5)=25∗20=500

and Area of Hall =20∗15=300

Area of verandah =500−300=200

Rate of 1 sq metre =17.5

Rate of 200 sq metre 17.50∗200=3500

XxinstaprincessxX

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