Question

A rectangular hall is 12 cm long and 6 cm broad. It's flooring is to be made of square tiles of side 30 cm. However many tiles will fit in the entire hall? How many would be required if tiles of side 15 cm were used?

Answer 1

Solution

The area of the floor of the hall =l ×b

$= > 12 \times 6 = 72m {}^{2}$

The area of 1 square tile

$= > \frac{30}{100} \times \frac{30}{100} = \frac{9}{100} m {}^{2}$

The number of tiles required

$= \frac{area \: of \: the \: floor \: }{area \: of \: one \: tile}$

$= > 72 \div \frac{9}{100} = \frac{72 \times 100}{9} = 800$

If the side of one tile is 15 cm

Its area =

$\frac{15}{100} \times \frac{15}{100} = \frac{3}{20} \times \frac{3}{20} = \frac{9}{400} m {}^{2}$

Therefore , the number of tiles acquired

$= > 72 \div \frac{9}{400} = \frac{72 \times 400}{9} = 3200$

THE FINAL ANSWER

i) 800 TILES

ii) 3200 TILES

Answer 2

Answer:

800 TILES AND 3200 TILES

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