Question

a rectangular hall is 12 m long and 6 m broad.its flooring is to be made of square tiles of Side 30 cm.how many tiles will fit in the entire hall?how many would be required if tiles of side 15 CM were used?

Answer 1

Area of rectangular hall = l×b

= 12×100×6×100

=720000 cm²     ∵1m =100cm

Area of 1 tile = l²

= 30×30                                                 =15×15

=900 cm²                                              =225 cm²

No. of tiles = Area of hall÷Area of 1 tile

=720000÷900                                     =720000÷225

=800 tiles                                            = 3200 tiles

Answer 2

$\tt ฏGIVEN:−$

$\tt length \: of \: floor = 4m =400cm$

$\tt breadth\: of \: floor= 3m = 300cm$

$\tt length\: of \: single \: tile= 8cm$

$\tt breadth\: of \: single \: tile= 6cm$

$\tt ฏFIND:-$

$\tt no. \: of \: tiles \: reqire = ?$

$\tt ฏSOLUTION:-$

$\tt area \: of \: floor = 400 \times 30 \\ \tt = 120000 {cm}^{2}$

$\tt area \: of \: each \: tile= 8 \times 6 = 4 {cm}^{2}$

$\tt now \: let \: no. \: of \: tiles = x$

$\tt = > area \: of \:hall= x\times area \: of \: each$

$\tt = > 120000 = x(48)$

$\tt = > x = \frac{ \cancel{ 120000}}{ \cancel{48}} = 2500$

$\boxed{ \tt so \: total \: no. \: of \: tile \: is \boxed{2500}}$