a rectangular hall is 18m72c.m and13m 20c.m broad.it is to be paved with square tiles of the same size.find the least possible no. of such tiles
Answers
Answered by
3
Given length of rectangular courtyard = 18 m 72 cm = 1872 cm
Width of rectangular courtyard = 13 m 20 cm = 1320 cm
To find the square tile of maximum side we take the HCG of 1872 and 1320 By Euclid’s division lemma
we have 1872 = 1320 × 1 + 552 1320 = 552 × 2 + 216 552 = 216 × 2 + 120 216 = 120
× 1 + 96 120 = 96 × 1 + 24 96 = 24 × 4 + 0 Hence the HCF is 24
Therefore maximum side of the square = 24 cm Number of tiles required = (Area of rectangular courtyard)
(Area of square tile) = (1872 × 1320)/(24 × 24) = 4290
Hence 4290 tiles are required.
Width of rectangular courtyard = 13 m 20 cm = 1320 cm
To find the square tile of maximum side we take the HCG of 1872 and 1320 By Euclid’s division lemma
we have 1872 = 1320 × 1 + 552 1320 = 552 × 2 + 216 552 = 216 × 2 + 120 216 = 120
× 1 + 96 120 = 96 × 1 + 24 96 = 24 × 4 + 0 Hence the HCF is 24
Therefore maximum side of the square = 24 cm Number of tiles required = (Area of rectangular courtyard)
(Area of square tile) = (1872 × 1320)/(24 × 24) = 4290
Hence 4290 tiles are required.
KGururaj1:
thank u sooooo much
Similar questions