Math, asked by prativa23, 9 months ago

a rectangular hall is ,5.25 m . long and 3.78 m wide . it's floor is to be covered with square tiles, each side 21cm. find the cost of tiles required at the rate of ₹5 per tile​

Answers

Answered by mittalkeshav795
7

Answer:

2250

Step-by-step explanation:

area of hall=525 cm ×378 cm =198450

area of tile=441

number of tiles= area of hall/area of tile

=450

cost of tiling= 5×450=2250

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Answered by Anonymous
14

Question

  1. A rectangular hall is 5.25 m long and 3.78 m wide. It's floor is to be covered with square tiles, each of side 21 cm. Find the cost of tiles required at the rate of ₹5 per tile.

Solution

\sf{Since, \:  \: floor  \: area \: of \: hall=5.25 \: m × 3.78 \: m} \\ \sf{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \: =525 ×378  \: cm²} \\ \sf{And, \:  \: area  \: of \: each \: tile=21 ×21 cm²} \\ \sf{Number \: of \: tiles \: required=\dfrac{Floor \: area \: of \: hall}{Area \: of \: each \: tile}} \\ \sf{\dfrac{525×378}{21×21}=450} \\ \sf{Since, \:  \:  \: cost \: of \: each \: tile \: =₹5} \\  \\ \sf{→The \: cost \: of \: all \: the \: tiles \: required=450×₹5=₹2,250}

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