Question

A rectangular has 15 cm as its length and 150cm² as its area. Its area is increased to 1⅓ times the original area by increasing only its length. it's new perimeter is ?​

Answer 1

Answer:

$\huge\underline{Question}$

A rectangular has 15 cm as its length and 150cm² as its area. Its area is increased to 1⅓ times the original area by increasing only its length. it's new perimeter is ?

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Given:

Length - 15 cm

Area - 150cm²

To Find:

Breadth - ?

New Perimeter - ?

Step by Step:

$breadth = \frac{area}{length}$

$= \frac{150}{15}$

$= 10cm$

New Area be:

$= 1 \frac{1}{3} \times 150 \: {cm}^{2}$

$= \frac{4}{3} \times 150 = 4 \times 50$

$= 200 \: {cm}^{2}$

New Length be:

$= (15 + h)cm$

$= \frac{200}{10} = 20$

h = 20 - 15 = 5 m

New Perimeter be:

$= 2(15 + 5) + 2 \times 10$

$= 40 + 20$

$= 60 \: cm$

Hope it will be helpful :)

Answer 2

Answer:

Lenght - 15 cm

Area - 150cm²

To Find:

Breadth - ?

New Perimeter - ?

Step by Step:

$Breadth = \frac{area}{length}$

$= \frac{150}{15}$

$= 10cm$

$New\:Area\:be:$

$= 1 \frac{1}{3} \times 150 \: {cm}^{2}$

$= \frac{4}{3} \times 150 = 4 \times 50$

$= 200 \: {cm}^{2}$

$New\:Length\:be:$

$= (15 + h)cm$

$= \frac{200}{10} = 20$

$h = 20 - 15 = 5 m$

$New\:Perimeter\:be:$

$= 2(15 + 5) + 2 \times 10$

$= 40 + 20$

$= 60 \: cm$