Question

a rectangular ink pad is 12 cm long then and 5 wide what is the perimeter?​

Answer 1

Step-by-step explanation:

Perimeter of ink pad = 2(length + breadth)

$= 2(12 + 5) \: cm$

$= 2 \times 17 \: cm$

$= 34 \: cm$

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Answer 2

Answer:

Step-by-step explanation:

Question :-

• A rectangular ink pad is 12 cm long and 5 cm wide. What is it's perimeter?

To Find :-

• Perimeter of ink pad.

Solution :-

Given :

• Length = 12 cm
• Breadth = 5 cm

By using the formula,

${\sf{\longrightarrow Perimeter\ of\ rectangle\ =\ 2(l\ +\ b)}}$

Where,

• l = length
• b = breadth

According to the question, by using the formula, we get :

${\sf{\longrightarrow Perimeter\ of\ ink\ pad\ =\ 2(l\ +\ b)}}$

${\sf{\longrightarrow 2(12\ +\ 5)}}$

${\sf{\longrightarrow 2(17)}}$

${\sf{\longrightarrow 2 \times 17}}$

${\sf{\longrightarrow 34\ cm}}$

$\therefore$ Hence, perimeter of ink pad is 34 cm.

More To Know :-

$\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}$