Question

a rectangular is formed by 100cm wire. find out the maximum area of the rectangle.​

Answer 1

length of wire is 100 cm

length of wire = perimeter of rectangle

$100 = 2(l + b) \\ l + b = \frac{100}{2} \\ l + b = 50$

we have to find maximum area . So, let

l = b .

Then,

$l + b = 50 \\ l + l = 50 \\ 2l = 50 \\ l = \frac{50}{2} \\ l = 25 \\ l = b = 25 \: cm$

Area of ∆

$= l \times b \\ = 25 \times 25 \\ = 625 \: { cm}^{2}$

Maximum area of ∆ is 625 cm² .

❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

FOLLOW ME ON INSTA @MALIKMOH.AMAN

Answer 2

Answer:

length of a wire=100cm

perimeter of rectangle=2(L+B)

• 100cm=2(L+B)
• 100cm/2=L+B
• L+B=50cm

NOW,

• L=B

when we take L=B the values are same.

• L+L=50cm
• 2L=50cm
• L=50cm/2
• L=25cm
• B=25cm

NOW, Area of a rectangle=L×B

• 25cm×25cm
• 625cm^2

So,area of a rectangle=625cm^2