Math, asked by diyqueen422, 19 days ago

a rectangular lawn 115 M long and 64 m board has to cross paths at right angle o n e 2 metre wide running parallel to its length and the other 2.5 M wide running parallel to its breadth find the cost of gravelling the path at ₹114 m square​

Answers

Answered by aakarshgoel2007
1

Answer:

1771 rs

Step-by-step explanation:

Length of a lawn(l) = 115m

Breadth of a lawn (b) = 64 m

Width of lengthwise road(PQ)= 2.5 m

Width of breadththwise road (AB)= 2 m.

Area of road( ABCD)= 115×2= 230 m²

Area of road( PQRS)= 64×2.5= 160 m²

Area of common path EFGH= 2× 2.5= 5 m²

Area of the roads= (Area of road ABCD+ Area of road PQRS) - Area of Road EFGH

Area of the roads= 230+160-5

Area of the roads= 390-5= 385 m²

Rate of gravel = ₹ 4.60 per m²

Cost of gravelling the roads= 385 × 4.60= 1771

Hence, the Cost of gravelling the roads = ₹1771

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