A rectangular lawn 115 m long and 64 m broad has two cross-paths at right-angles, one 2 m wide,
running parallel to its length and the other 2.5 m wide, running parallel to its breadth. Find the
cost of gravelling the paths at 114 per m2.
Answers
Step-by-step explanation:
Let ABCD be the rectangular field and PQRS and KLMN be the two rectangular roads with width 2 m and 2.5 m, respectively.
Length of the rectangular field, CD = 115 cm
Breadth of the rectangular field, BC = 64 m
∴ Area of the rectangular lawn ABCD = 115 m 64 m = 7360 m2
Area of the road PQRS = 115 m 2 m = 230 m2
Area of the road KLMN = 64 m 2.5 m = 160 m2
Clearly, the area of EFGH is common to both the two roads.
∴ Area of EFGH = 2 m 2.5 m = 5 m2
∴ Area of the roads = Area (KLMN) + Area (PQRS) − Area (EFGH)
= (230 m2 + 160 m2) − 5 m2 = 385 m2
Rate of gravelling the roads = Rs 60 per m2
∴ Total cost of gravelling the roads = Rs (385 60)
= Rs 23,100
the answer is very easy see the image and understand the answer.
