Question

a rectangular lawn 60 by 40 metre has two Cross Roads each 5 metre wide running in the middle of it length one parallel to length and the other parallel to the breadth find the cost of gravelling them at 2.60 per square metre​

Answer 1

Answer:

FOR RECTANGULAR LAWN.

Length, L = 80m.

Breadth, B= 60m.

For Vertical road:

length= Breadth of rectangle

length = 60m.

Breadth = 10m.

Thus, Area of vertical road

=length × breadth

= 60m ×10m

=600m².

For Horizontal road:

length = length of rectangle.

length = 80m

breadth= 10m.

Thus, area of horizontal road

= length ×breadth

= 800m × 10m

=800m².

Note: The roads overlap in the middle of rectangle and form a square having side of 10m.

FOR SQUARE:

Area of square = Side × Side

Area of square = 10m × 10m

Area of square = 100m².

Therefore,

Area needd of road to be gravel

= Area of vertical road + area of horizontal road - area of square

= 600m² + 800m² -100m²

= 1300m².

If the cost of gravelling for 1m² = Rs 1.20

So, Cost of gravelking for 1300m²

= 1300 ×Rs 1.20

=Rs 1,560. Ans.