Question

A rectangular lawn 70 m by 50 m has two roads each 5 m wide running through its middle one parallel to its length and the other parallel to its breadth find the cost of constructing the roads at ruppes 120 per m2

Answer 1

Answer:

Let EFGH and IJKL be the two rectangular roads with width 5 m.

Length of the rectangular park, AD = 70 m

Breadth of the rectangular park, CD = 50 m

∴ Area of the rectangular park = Length×Breadth = 70×50 = 3500 m²

Area of road EFGH = 70×5 = 350 m²

Area of road IJKL = 50×5 = 250 m²

Clearly, area of MNOP is common to both the two roads.

∴ Area of MNOP = 5×5 = 25 m²

Area of the roads,

= Area of (EFGH) + Area of (IJKL) − Area of (MNOP)

= (350 + 250 ) m²− 25 m²

= 575 m²

It is given that the cost of constructing the roads is Rs. 120/m².

Cost of constructing 575 m² = Rs. (120 × 575)

= Rs. 69000

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