a rectangular lawn 70m by 50m has tow roads, each 5 m wide, running through its middle, one parallel to its length and the other parallel to its breadth. fine the cost of constructing the road at rupees 120per m square
Answers
Answered by
2
Area of the road parallel to the length= 70m×5m= 350m^2
Area of the road parallel to the breadth= 50m×5m=250m^2
Area of the portion of the road overlapping= 5m×5m=25m^2
Total area of the road= (350m^2 + 250m^2)- 25m^2 = 575m^2
Cost of constructing the road at rupees 120per m square= 120×575= Rs. 69,000
Area of the road parallel to the breadth= 50m×5m=250m^2
Area of the portion of the road overlapping= 5m×5m=25m^2
Total area of the road= (350m^2 + 250m^2)- 25m^2 = 575m^2
Cost of constructing the road at rupees 120per m square= 120×575= Rs. 69,000
Similar questions