A rectangular lawn, 75m by 60m ,has two roads , each 4 m wide , running through the middle of the lawn , one parallel to length and other parallel to breadth . Find the cost of gravelling the raids at 45 per m².
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Heya !!!
Let ABCD and EFGH are two roads.
Length of road ABCD = 75 m
And,
Breadth of road ABCD = 4 m
Area of road ABCD = (75 × 4) = 300 m².
Length of road EFGH = 60 m
And,
Breadth of road EFGH = 4 m
Therefore,
Area of road EFGH = ( 69 × 4) = 240 m².
And,
Area of square formed by the intersection of two roads = ( 4 × 4) = 16 m².
Therefore,
Area of the roads to be gravelled =
Area of road ABCD + Area of road EFGH - Area of square = 300 + 240 - 16 = 524 m².
Cost of 1 m² of gravelling = rs 45
Therefore,
Cost of 524 m² of gravelling = 45 × 524 = Rs 23580.
HOPE IT WILL HELP YOU...... :-)
Let ABCD and EFGH are two roads.
Length of road ABCD = 75 m
And,
Breadth of road ABCD = 4 m
Area of road ABCD = (75 × 4) = 300 m².
Length of road EFGH = 60 m
And,
Breadth of road EFGH = 4 m
Therefore,
Area of road EFGH = ( 69 × 4) = 240 m².
And,
Area of square formed by the intersection of two roads = ( 4 × 4) = 16 m².
Therefore,
Area of the roads to be gravelled =
Area of road ABCD + Area of road EFGH - Area of square = 300 + 240 - 16 = 524 m².
Cost of 1 m² of gravelling = rs 45
Therefore,
Cost of 524 m² of gravelling = 45 × 524 = Rs 23580.
HOPE IT WILL HELP YOU...... :-)
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