Question

A rectangular lawn 75m by 60m has two roads each 4m wide, running through the middle of the lawn one parallel to length and the other parallel to breadth as shown in figure. Find cost of gravelling the roads at Rs 4.50 per m^2 ?

Answer 1

$\bf\huge\textbf{\underline{\underline{According\:to\:the\:Question}}}$

Area of Road ABCD

= 75 × 4

= 300

Area of Road EFGH

= 60 × 4

= 240

As in figure PQRS is common for both roads

Area of PQRS

= 4 × 4

= 16

Road to be Gravelled

= 300 + 240 - 16

= 524 m^2

Now cost will be

= 524 × 4.50

$\bf\huge\bf\huge{\boxed{\bigstar{{Rs\:2358}}}}$          

Answer 2

Answer:

Step-by-step explanation:

TOAL AREA = (L+B -W) W

                  =(75+60-4)4

                 =131X4

                =524

COST =524X4.5 =524 X9/2 =262 X9 = 2358