a rectangular lawn 80 metre ×60 metre has two roads is 10 metre wide running in the middle of 81 parallel to the length and the other parallel to the breath. find the cost of travelling them much rupees 1.20 per square metre
Answers
The cost of gravelling them at Rs. 1.20 per square meter = Rs . 1560
To find the area of roads :
It is given that
a rectangular lawn 80 m × 60 m has two roads each 10 m wide running in the middle of it.
Dimension of two roads are 80×10 and 60×10
Area of two roads = 80×10+60×10−10×10
=800+600−100
= 1300 sq. meter
To find the cost for gravelling
It is given that
The cost of gravelling the at Rs. 1.20 per sq. meter.
Therefore total cost = total area × cost per sq. meter
=1300×1.20
=Rs.1560
∴ The cost of gravelling them at Rs. 1.20 per sq. meter = Rs. 1560
Answer:
Rs.39000
Step-by-step explanation:
In rectangular road PQRS, l=60m,b=10m
⇒ Area of rectangle PQRS=l×b=60×10=600 sq.m
⇒ In rectangular road ABCD, l=80m,b=10m
⇒ Area of rectangle ABCD=l×b=80×10=800 sq.m
⇒ Total area of two roads =600 sq.m + 800 sq.m = 1400 sq. m
⇒ But square EFGH is common in both road.
∴ Area of EFGH=10²=100m ²
∴ Final area of two roads =1400−100 = 1300m ²
∴ Cost of gravelling the roads =1300×30 = Rs.39000