Math, asked by Anonymous, 4 months ago

A rectangular lawn 86.5 by 54.5 is constructed to path is 2.5 metre wide are cut across the middle one parallel to the length and the other parallel to the breadth find the area of path and cost of levelling one corner person at rupees 1.45 per square metre

Answer-346.25m²,Rs.1583.40
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Answers

Answered by Anonymous
4

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A rectangular lawn 86.5 by 54.5 is constructed to path is 2.5 metre wide are cut across the middle one parallel to the length and the other parallel to the breadth find the area of path and cost of levelling one corner person at rupees 1.45 per square metre.

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area \: of \: rectangle = l \times b

length \: and \: bradth \: are \: 86.5 \: and \: 54.5

formula \\ a = l \times b

a = 86.5 \times 54.5

a = 47142.25 {m}^{2}

area \: of \: total \: road

 = (2.5 \times 86.5) + (2.5 \times 54.5) - 6.25

 = 216.25 + 136.25 - 6.25

 {\boxed {\boxed {= 346.25 {m}^{2}}}}

all \: corners \: have \: same \: area

let \: one \: corner \: be \: as \: x

let \: four \: corners \: be \: as \: 4x

 = 346.25 + 4x = 4714.25

  4x = 4714.25 - 346.25

4x = 4368

x =  \frac{4368}{4}

x = 1092 {m}^{2}

cost \: of \: leveling \: for \: 1 {m}^{2}  = 1.45 \: rupees

cost \: of \: leveling \: for \: 1092 {m}^{2}

 = 1092 \times 1.45

{\boxed {\boxed {= 1583.40 \: rupees}}}

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