A rectangular lawn is 30 m by 20 m. It has two roads each 2 m wide running in the middle of it, one parallel to the length and other parallel to the breadth. Find the area of the roads.
Answers
breadth (b) =20
wide (w) = 2 m
area of roads =( l+b-w)w
= (30+20-2).2
= (48).2
= 96 square m
Given:
Length of rectangular lawn=30m
Width of rectangular lawn=20m
Width of roads= 2m
To find:
The area of the roads
Solution:
We can find the solution by following the given steps-
We are given that each road is parallel to the length and width of the lawn.
So, the length of the 2 roads is 30m and 20m.
Area of road parallel to the length of lawn= length of lawn× width of the road
=30×2
=60m²
Area of road parallel to the width of lawn= width of lawn× width of the road
=20×2
=40m²
But there is a square area at the intersection of the two roads which needs to be deducted.
Area of the square at intersection= (width of the road)²
=2×2
=4 m²
The total area of the roads= area of both roads- the area of intersection
=60+40-4
=96m²
Therefore, the area of the roads is 96m².