Math, asked by shekharjaiswal29633, 5 months ago

a rectangular lawn measuring 50 metre by 40.5 metre as 200 2.5 and 1.8 white running in the middle of it one parallel to its length and the other parallel to its breadth find the cost of cementing the road at 24 per metre square

Answers

Answered by 2008shrishti
3

Answer:

Rs.285

Step-by-step explanation:

Given,

A rectangular lawn 60 meters by 40 meters has two roads each 5 meters wide running in the middle of it one parallel to length and the other parallel to breadth

Area of the road=40×5+60×5−5×5

=200+300−25

=475sqm

Given,

Cost of graveling the roads =60 paise per sq meter.

∴475×60paise

=28500 paise

=Rs.285

Hope this answer will help you

Answered by akhilmukkara
1

Answer:

Step-by-step explanation:

Area of the longer road=2×50=100m^2

Area of the smaller Road =

2.5×40= 100 m^2

area of fields=50×40=2000m^2

area common to both the road

=2.5×2=5m^2

area of roads=200-5=195

=1805m^2

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