Question

a rectangular lawn measuring 70m by 50m is having two cross roads of width 5m running through its middle parallel to its length and other parallel to its width . find the area of roads​

Answer 1

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 50 m

area of second road =50×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105