A rectangular lawn of length 40 m and breadth 25 m is to be surrounded externally by a path which is
2 m wide. Find the area of the path.
Answers
Answer:
Step-by-step explanation:
Area of ABCD
Given length = 40m
Given breadth = 25m
Area = Length × breadth
= 40m × 25m
= 1000m^2
External path = 2m wide
Length =40m+2m+2m=44m
Breadth = 25m+2m+2m= 29m
Area of PQRS= Length × breadth
44m ×29m = 1276m^2
Area of path = Area of PQRS - Area of ABCD
= 1276m^2 - 1000m^2
= 276m^2
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Question:-
A rectangular lawn of length 40m and breadth 25 m is to be surrounded externally by a path which is 2m wide.
Find the area of the path.
solution:-
Let, L be the length of rectangle and B be
the breadth rectangle.
By Question:-
We know formula of
=> Area of rectangle = L × B
=> Area of rectangle = 40 × 25
=> Area of rectangle = 1000 m²
=> X = 1000 m²
we know that length and breadth increase by 2 m from their both ends.
so,
=> L = 40 + 2 + 2 = 44 m.
=> B = 25 + 2 + 2 = 29 m.
We know formula of
=> Area of rectangle + path = L × B
=> Area of rectangle + path
= 44 × 29
=> Area of rectangle + path
= 1276 m²
=> Z = 1276 m²
=> Area of path =( Z ) - ( X )
=> Area of path = 1276 - 1000
=> Area of path = 276 m²
Hence area of path 276 m².
i hope it helps you.