Question

A rectangular loop carrying current is placed near a long staight fixed wire carrying strong current such that long sides are parallel to the wire. if the current in the nearer long side of the loop is parallel to current in the wire then the loop​

Answer 1

Answer:

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Answer 2

Answer:

ANSWER

The long straight wire and side AB carry current in the same direction, hence will attract each other.

The long straight wire and side CD carry current in the opposite direction, hence will repel each other.

Force on side BC will be equal and opposite to force on side DA.

Since CD is farther from the wire than AB, the force of attraction on AB will exceed the force of repulsion on CD.

Hence, there will be a net force of attraction on the loop ABCD and it will move towards the wire.

solution