Question

A rectangular loop of area 20 cm × 30 cm is placed in a magnetic field of 0.3 t with its plane 1) normal to the field 2) inclined 30° to the field 3) parallel to the field. find the flux linked woth the coil in each case

Answer 1

Hello friend,

Following is the answer to your question,

Hope it helps.

Here A = 20cm x 30 cm = 6 x ${{10}^{-2}}$${{m}^{2}}$

B = 0.3 T

Let θ be the angle made by the field B with the normal to the plane of the coil.

(i) Normal to the field i.e. , θ = 90°- 90° = 0°

so,flux, = BA Cos θ

= 0.3 x 6 x ${{10}^{-2}}$ x cos0°

= 1.8 x ${{10}^{-2}}$ Wb

(ii) Inclined 30° towards the plane i.e., θ = 90° - 30° = 60°

= 0.3 X 6 X ${{10}^{-2}}$ x cos 60°

= 0.9 x ${{10}^{-2}}$ Wb

(iii) Parallel towards the plane i.e. , θ = 90°

= 0.3 X 6 X ${{10}^{-2}}$ x cos90°

= θ

Thank you.

Answer 2

Answer:

HOPE THE ABOVE GIVEN ATTACHMENT WILL HELP YOU......