Question

a rectangular loop of dimensions 0.04 into 0.05 metre is situated in a uniform vertical magnetic field of intensity 0.80 weber per metre square. the magnetic flux passing through the loop when the plane of the loop is horizontal

Answer 1

Magnetic flux = B.dS

Here dS = 0.04*0.05

= 0.002 m^2

Flux = BdS cos theta

Here cos theta is the angle between are vector and the magnetic field...which is equal to 0 and we know that cos 0° = 1

Therefore flux = 0.8* 0.002

Flux = 16 *10^-4 Wb