Question

 A rectangular loop of dimensions 0.50m and 0.60m is placed in a magnetic field of induction 0.02T. Determine the magnetic flux through the surface.​

Answer 1

your complete question is => The Dimension of a rectangular loop is 0.50m and 0.60m. B and θ are 0.02T and 45° respectively. Determine the magnetic flux through the surface.

solution : magnetic flux through the surface is given by, Φ = BA cosθ

here, B = magnetic field intensity = 0.02 T

A = surface area of rectangular surface = 0.50 m × 0.60 m = 0.30 m²

θ = angle between B and A = 45°

so, Φ = 0.02 T × 0.3 m² × cos45°

= 0.006 cos45° Wb

= 0.0042426 Wb

Therefore the electric flux through the surface is 0.0042426 Wb

Answer 2

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