Math, asked by ashishtripathi39, 1 year ago

A rectangular lwan is 30 m by 20 it has two roads each 2m wide running in the middle of it ,one parallel to the length and the parallel to the breadth. find the area of the road

Answers

Answered by anjali9999
2
here is your ans. and hope will help u...
Attachments:

ashishtripathi39: yes
anjali9999: in which school fo u read?
avyaytulsyan: No, this answer is correct
anjali9999: thank u avyay for thanking my ans.
ashishtripathi39: but 224 m2in answer sheet
anjali9999: i have this question in my text book snd THE ans is 96 m2
ashishtripathi39: bhai mere me etna hi hai
anjali9999: dont worry some times it happens
anjali9999: but the ans is 96 m2
ashishtripathi39: ok thankx
Answered by avyaytulsyan
1

Answer:

The answer is 96 square meters.


Step-by-step explanation:

First we need to find the area of the road parallel to the breadth:

It's length=20 m

It's breadth/width=2 m

It's area=2 m x 20 m = 40 square meters

Then we find the area of the road parallel to the length:

It's length=30 m

It's breadth/width=2 m

It's area=30 m x 2 m= 60 square meters

Since the two roads overlap in the middle, we must find and subtract the area of intersection, otherwise it will have been counted twice. The dimensions of the intersection will be the widths of the respective pathways.

Length of intersection=2 m

Breadth/Width of intersection=2 m

Area of intersection=2 m x 2 m= 4 square meters

So,

Area of the road= 100 square meters-4 square meters=96 square meters


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