Question

a rectangular mat of 5 m×3.5 m had a border of width 1.8 m all around it.if the cost of the mat is ₹272/m²,find the cost for bordering the mat.
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Answer 1

ANSWER

Given inner side of square park, s=100 cm

Area of inner square =100

2

=10000 cm

2

width of path,w=5 cm

Outer side of square =100+5+5=110 cm

Area of outer square =110

2

=12100 cm

2

Area of path =12100−10000=2100 cm

2

Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500

∴ Cost of cementing a 2100 cm

2

path =Rs. 52500

Answer 2

Length= 5m

Breath= 3.5m

Cost of the mat= Rs.272/m²

Area of mat = 5 m× 3.5 m = 17.5m²

Length= 5+ 1.8+ 1.8= 8.6m

Breath= 3+ 1.8+ 1.8= 7.1m

Area of rectangle= L× B= 8.6×7.1= 61.06

Area of Border= 61.06- 17.5= 43.56m²

Cost of bordering= 272× 43.56= Rs.11,848.32