Question

A rectangular metal block of mass 4 kg rests on the top of a metal surface.
The coefficient of friction between the box and the metal surface is 0.2.
What force parallel to the surface is needed to move the block.
(8N)
69​

Answer 1

Answer:

8 newton

Explanation:

since, normal force acting on surface = weight of the block = mg = 4×10 = 40 N

since, friction force between surface and block =

= ( coefficient of friction× normal force)

= 0.2×40 = 8N

therefore, force parallel to the surface is needed to move the block= frictional force acting between them.

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