Math, asked by BLACKANGEL38, 11 months ago

a rectangular metal block X measuring 12 cm by 8 cm by 4 cm, is melted and recast into a rectangular block Y, 2 cm wide and 1 cm high. Find the ratio of the total surface area of block X to that of block Y.​

Answers

Answered by demonempire135
2

Answer:

the ratio of the TSA of the XandY is 3: 5

Answered by mpneelamporwal
12

Step-by-step explanation:

x has volume =12×8×4

= 384 cm³

y volume = 2×1×x ( here x is length )

= 2x

now

x volume = y volume

384=2x

192 = x

now

total surface area of x is

2(lb+bh+hl)

2(12×8+8×4+4×12)

2(96+32+48)

2(176)

352 cm²

now total surface area of y

2(LB+BH+HL)

2(192×2+2×1+1×192)

2(384+2+192)

2(578)

1156 cm²

ratio

352/1156

88:299

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