a rectangular metal block X measuring 12 cm by 8 cm by 4 cm, is melted and recast into a rectangular block Y, 2 cm wide and 1 cm high. Find the ratio of the total surface area of block X to that of block Y.
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2
Answer:
the ratio of the TSA of the XandY is 3: 5
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Step-by-step explanation:
x has volume =12×8×4
= 384 cm³
y volume = 2×1×x ( here x is length )
= 2x
now
x volume = y volume
384=2x
192 = x
now
total surface area of x is
2(lb+bh+hl)
2(12×8+8×4+4×12)
2(96+32+48)
2(176)
352 cm²
now total surface area of y
2(LB+BH+HL)
2(192×2+2×1+1×192)
2(384+2+192)
2(578)
1156 cm²
ratio
352/1156
88:299
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