A rectangular metal box is 30 m long and 15 m broad. If the sum of the areas of the base and the top is equal to its lateral surface area, then (i) The height of the box is
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Given that l=20cm, b=12cm, h=9cm
∴T.S.A=2(lb+bh+lh)
=2[(20×12)+(12×9)+(20×9)]
=2(240+108+180)
=2×528
∴T.S.A=1056cm 2
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