Question

a rectangular paper has a length of 5 2/3cms and breadth of 3 1/5cms.Find it's perimeter?? ​

Answer 1

Answer:

17.7333 cms

Step-by-step explanation:

length of rectangular paper = 5 2/3 cm = 17/3 cm

breadth of rectangular paper = 3 1/5 cm = 16/5 cm

perimeter of rectangle = 2(l + b)

$= 2( \frac{17}{3} + \frac{16}{5} ) \\ = 2( \frac{(17 \times 5) + (16 \times 3)}{15} ) \\ = 2( \frac{85 + 48}{15} ) \\ = 2( \frac{133}{15} ) \\ = \frac{266}{15} \\ = 17 \frac{11}{15} \\ = 17.733 \: cm$

hope you get your answer

Answer 2

Answer:

Perimeter of rectangle =47.06

Step-by-step explanation:

52/3= 17.33

31/5= 6.2

Perimeter of rectangle =2(l+w)

=2(17.33+6.2)

=2(23.53)

=47.06