A rectangular paper is 22 cm long and 10 cm wide. It is folded without overlapping to make a cylinder of height 10 cm. Find the volume of the cylinder.
Answers
Answer:
⠀⠀⠀⌬ Length of paper = 22 cm
⠀⠀⠀⌬ Width of paper = 10 cm
When we will overlap it, Width is becoming Height pf cylinder but Length will become Circumference of Base of cylinder.
• Circumference of Base :
⇒ 2πr = 22
⇒ 2 × 22/7 × r = 22
⇒ r = 22 × 7/(22 × 2)
⇒ r = 7/2 cm
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⠀⠀⠀⌬ Radius of cylinder = 7/2 cm
⠀⠀⠀⌬ Height of cylinder = 10 cm
• Volume of Cylinder :
⇢ Volume = πr²h
⇢ Volume = 22/7 × (7/2)² × 10
⇢ Volume = 22/7 × 7/2 × 7/2 × 10
⇢ Volume = 22 × 1/2 × 7/2 × 10
⇢ Volume = 11 × 7 × 5
⇢ Volume = 385 cm³
∴ Volume of cylinder formed is 385 cm³.
HOPE THIS HELPS YOU :
Length of the rectangular paper will be height of the cylinder and width of the rectangular paper is circumference of the cylinder
∴2 πr = 10cm and h = 22cm
Now volume of the cylinder
= πr²h
= 22/7 × 10/2π × 10/2π ×22cm³
= 22/7 × 10/2 × 7/22 × 10/2 × 7/22 × 22cm³
= 175cm³
Therefore, volume of the cylinder is 175 cm³.