A rectangular paper of length 66 cm and breadth 14 cm is rolled into a cylinder along the length. Find total aurface area and volume of cylinder.
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when we roll the paper along the length the height will be it's length that is 66 cm and circumference of base will be 14 cm
so 2*π*r = 14
r = 14/2*π
r = 7/π
total surface area of cylinder = 2π r ( r + h)
= 2 π *7/π ( 7/π + 66)
= 14( 49/22 + 66)
14( 49+ 1452)/22
= 955.1818 cm^2
volume = π r^2 h
= π * (7/π) * (7/π) *66
= 49*66*7/22 = 1029 cm^3
so 2*π*r = 14
r = 14/2*π
r = 7/π
total surface area of cylinder = 2π r ( r + h)
= 2 π *7/π ( 7/π + 66)
= 14( 49/22 + 66)
14( 49+ 1452)/22
= 955.1818 cm^2
volume = π r^2 h
= π * (7/π) * (7/π) *66
= 49*66*7/22 = 1029 cm^3
muskannayal27:
And u know my ans. Was also coming same . that rectangular one...
and what is the cube of 7 that is 343 and it ends wirh 3
Yes my ans. Was also true
yes
so i think your exam webt good
No ....
Many more questions r the
if you need help in them you can ask me
OK thanks...
you are most welcome
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