Question

a rectangular paper of length 66cm and breadth 14cm is rolled into a cylinder along the length. find the total surface area and volume of the cylinder.

Answer 1

Answer:

54cm2

Step-by-step explanation:

tsa =?

v=?

tsa =2{lb+bh+lh}

     =2 * 27

     = 54 cm2

Answer 2

Answer:

• Total surface area of the cylinder is 955.22 cm² .

• Volume of the cylinder is 1029 cm³.

Step-by-step explanation:

Given :-

• A rectangular paper of length 66 cm and breadth 14 cm is rolled into a cylinder along the length.

To find :-

• Total surface area and volume of the cylinder.

Solution :-

• Length of the rectangular paper = 66 cm.
• Breadth of the rectangular paper = 14 cm.

The rectangular paper is rolled into a cylinder.

Then,

Circumference of base = Breadth of rectangle

★ Formula used :

${\boxed{\sf{Circumference\:of\:base=2\pi\:r}}}$

According to the question,

2πr = 14

→ 2×(22/7)×r = 14

→ r = 14×(1/2)×(7/22)

→ r = 49/22

Radius of the cylinder =49/22 cm.

Length of the rectangular paper = Height of the cylinder.

• Height of the cylinder = 66 cm

Total surface area of the cylinder,

= 2πr(h+r)

= 2×(22/7)×(49/22)×[66+(49/22)] cm²

= 14(66+2.23) cm²

= 14 × 68.23 cm²

= 955.22 cm²

Therefore, the total surface area of the cylinder is 955.22 cm².

Volume of the cylinder,

= πr²h

= (22/7)×(49/22)×(49/22)×66 cm³

= 7×49×3 cm³

= 1029 cm³

Therefore, volume of the cylinder is 1029 cm³.