Question

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
A) 1
B) 2
C) 3
D) 4

Answer 1

Answer:   C) 3 

Explanation:

Area of the park = (60 x 40) = 2400m2

Area of the lawn = 2109m2 

Area of the crossroads = (2400 - 2109) = 291m2 

Let the width of the road be x metres. Then,

60x+40x-X2=291 

x2-100x+291=0 

  (x - 97)(x - 3) = 0
   x = 3.

Answer 2

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
A) 1
B) 2
C) 3
D) 4

=> Option C

Description:

Area of the park = (60 x 40) = 2400m^2

Area of the lawn = 2109m^2

Area of the crossroads = (2400 - 2109) = 291m^2

Let the width of the road be x metres. Then,

=> 60x+40x−x^2=291

=> x^2−100x+291=0

=> (x - 97)(x - 3) = 0

=>  x = 3.