A rectangular park 60 m long as well as 40 m wide has two concrete crossroads running in middle of park as well as rest of park has been used as the lawn. in case area of lawn has been 2109 sq. m what has been width of road? ticka 2.91 m tickb 3 m tickc 5.82 m tickd none of these
Answers
Answer – Width of the cross road = 3 m.
Solution –
Given – Length = 60 m
Breadth = 40 m
Area of the Park = L * B
= 60 * 40
= 2400 m2
Area of the Lawn = 2109 m2
Area of the cross road = Area of the Park – Area of the Lawn
= 2400 – 2109
= 291 m2
Let us assume, the width of the cross road be X m
Hence,
Area of the cross road = Area of the horizontal cross road + Area of the vertical cross road - Area of the intersection of the cross road
291 = 60 X + 40 X – X2
X2 - 100X + 291 = 0
X2 - 97X - 3 X + 291 = 0
X (X – 97) -3 (X – 97) = 0
(X – 97) (X – 3) = 0
X = 97 or X = 3
In this case X = 3 because total width of the park is 40m so width of the cross road should be less than 40m.
Answer – Width of the cross road = 3 mAnswer:
Step-by-step explanation:
There are N people sitting around a circular table. Let’s call them P1, P2, . . . , PN , in order. P1 is sitting between P2 and PN .P2 is sitting between P1 and P3. P3 is sitting between P2 and P4, and so on.
You need to select a non-empty subset of these people, such that no two adjacent people are selected. Find the total number of ways in which you can do so.