. A rectangular park 78m long and 35m broad has a uniform path 1m wide all around it on the outside.The area of path is
Answers
The area of the Path is 170 m².
\mathfrak{\large{\underline{\underline{Explanation :-}}}}
Explanation:−
Given :
Rectangular Ground's Length = 78 m
Breadth of the Rectangle = 5 m
Width of the Path = 1 m
To Find :
The area of the Path
Solution :
★ Area of the Path = Area of Bigger Rectangle - Area of smaller Rectangle
\rule{300}{1.5}
Area of the Smaller Rectangle :
★ \boxed{\sf{Area = Length \times Breadth}}
Area=Length×Breadth
\sf{\implies} \: 78 \times 5⟹78×5
\sf{\implies} \: 390⟹390
Area of the Smaller Rectangle = 390 sq.m
\rule{300}{1.5}
Area of the Bigger Rectangle :
★ \boxed{\sf{Area = Length \times Breadth}}
Area=Length×Breadth
Length = 78 + (1 + 1) = 80
Breadth = 5 + (1 + 1) = 7
\sf{\implies} \: 80 \times 7⟹80×7
\sf{\implies} \: 560⟹560
The Area of the Bigger Rectangle is 560 sq.m
\rule{300}{1.5}
Area of the Path :
\sf{\implies} \: 560 - 390⟹560−390
\sf{\implies} \: 170⟹170
\therefore∴ The area of the Path is 170 m².
Answer:
230m(square)
Step-by-step explanation:
Area of inner rectangle (park) = length * breadth
= 78m * 35m
= 2730m(square)
New length= 78m+ width of path+ width of path= 78m+1m+1m= 80m
New breadth= 35m+ 1m+ 1m= 37m
Area of outer reactangle (park with path) = length * breadth
= 80m * 37 m
= 2960m(square)
Thus, Area of path= Area of outer- Area of inner rectangle
= 2960m(square)-2730m(square)
= 230m(square)
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