a rectangular park has dimension 90m by 70m .tow paths run parallel to the length of the rectangle and two paths run parallel to its breadths. the two paths along the length are 7m wide and the other two along the breadth are 5m wide.find the area of:. (a) all the paths (b) the remaining portion of the park
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a. length of path running parallel to length =90m
breadth of the path=7m
area=90*7m²=630m²
area of two paths =630m²*2=1260m²
now length of path running parallel to the breadth=70m
breadth of path=5m
area=70*5m²=350m²
area of two path=350m²*2=700m²
so total area of path =1260+700m²=1960m²
b. total area of park =90*70m²=6300m²
so area of park left=6300m²-1960m²
=4340m²
breadth of the path=7m
area=90*7m²=630m²
area of two paths =630m²*2=1260m²
now length of path running parallel to the breadth=70m
breadth of path=5m
area=70*5m²=350m²
area of two path=350m²*2=700m²
so total area of path =1260+700m²=1960m²
b. total area of park =90*70m²=6300m²
so area of park left=6300m²-1960m²
=4340m²
Answered by
0
Area of the two paths along the length = 2 x (90m x 7m) = 1260m²
Area of the two paths along the breadth = 2 x (70m x 5m) = 700m²
Area of the paths crossing each other = 4 x (7m x 5m) = 140m²
Therefore, total area of the path = (1260 + 700 - 140) m²
= 1820m²
Area of the park = 90m x 70m = 6300m²
Therefore, area of the remaining portion = (6300 - 1820) m²
= 4480m²
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