a rectangular park is 100m by 50m.it is surrounded by a semi circular flower beds all round. find the cost of levelling the semi circular flower bed at rupees 50 per m2 (use π=3.14)
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nileshjaiswal445:
thanks but the given answer without solution is rupees 490625
in my book
and is a semi circular flower bed not circular
i will send you the correction by 7 o clock
ok
dekh liya apane ans
Answered by
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length of rectangular park=100m
breadth ofrectangular park=50m
Area of rectangular park=length×breadth
=(100×50)m^2
=5000m^2
length side radius of semicycle flowers bed=50m
2Area of semicycle flowers bed=pai×r^2)/2
=2(3.14×50×50)/2
=2(3.14×1250)m^2
=(2×3925)m^2
=7850m^2
breadth side radius of semicycle flowers bed=50/2=25m
Area of breath side semicycle flowers bed=(pai×r^2)/2
=(3.14×25×25)/2
=981.25m^2
total area of flowers bed= 7850+ 981.25
= 8,831.25m^2
cost of per metre square=50rs
cost of 8,831.25m^2= (8,831.25×50)rs
= 441,562.5rs
breadth ofrectangular park=50m
Area of rectangular park=length×breadth
=(100×50)m^2
=5000m^2
length side radius of semicycle flowers bed=50m
2Area of semicycle flowers bed=pai×r^2)/2
=2(3.14×50×50)/2
=2(3.14×1250)m^2
=(2×3925)m^2
=7850m^2
breadth side radius of semicycle flowers bed=50/2=25m
Area of breath side semicycle flowers bed=(pai×r^2)/2
=(3.14×25×25)/2
=981.25m^2
total area of flowers bed= 7850+ 981.25
= 8,831.25m^2
cost of per metre square=50rs
cost of 8,831.25m^2= (8,831.25×50)rs
= 441,562.5rs
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thanks but ans is rupees 490625
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