A rectangular park is 100m by 50m. It is surrounded by semi-circular flower bed sall round. Find the cost of leveling the semi-circular flower bed sall 60paise per square meter.(Use π=3.14)
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Step-by-step explanation:
Length of rectangular park=100m
breadth ofrectangular park=50m
Area of rectangular park=length×breadth
=(100×50)m^2
=5000m^2
length side radius of semicycle flowers bed=50m
2Area of semicycle flowers bed=pai×r^2)/2
=2(3.14×50×50)/2
=2(3.14×1250)m^2
=(2×3925)m^2
=7850m^2
breadth side radius of semicycle flowers bed=50/2=25m
Area of breath side semicycle flowers bed=(pai×r^2)/2
=(3.14×25×25)/2
=981.25m^2
total area of flowers bed= 7850+ 981.25
= 8,831.25m^2
cost of per metre square=50rs
cost of 8,831.25m^2= (8,831.25×50)rs
= 441,562.5rs
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