Math, asked by RITIKKUMAR4644, 11 months ago

A rectangular park is 100m by 50m. It is surrounded by semi-circular flower bed sall round. Find the cost of leveling the semi-circular flower bed sall 60paise per square meter.(Use π=3.14)

Answers

Answered by pandeysakshi200310
1

Step-by-step explanation:

Length of rectangular park=100m

breadth ofrectangular park=50m

Area of rectangular park=length×breadth

=(100×50)m^2

=5000m^2

length side radius of semicycle flowers bed=50m

2Area of semicycle flowers bed=pai×r^2)/2

=2(3.14×50×50)/2

=2(3.14×1250)m^2

=(2×3925)m^2

=7850m^2

breadth side radius of semicycle flowers bed=50/2=25m

Area of breath side semicycle flowers bed=(pai×r^2)/2

=(3.14×25×25)/2

=981.25m^2

total area of flowers bed= 7850+ 981.25

= 8,831.25m^2

cost of per metre square=50rs

cost of 8,831.25m^2= (8,831.25×50)rs

= 441,562.5rs

last step in pipic

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