Question

A rectangular park is 40 m long and 30 m wide. A path of 5 m runs round the inside of the park. Find the area of the path​

Answer 1

Answer:

I will give answer next time

Answer 2

✫Question:-

A rectangular park is 40 m long and 30 m wide. A path of 5 m runs round the inside of the park. Find the area of the path.

ㅤㅤㅤ᯽︎Given:-

• Length of rectangle =40m

• Breadth of rectangle = 30m

ㅤ

ㅤㅤ✻To Find:-

• Area of the path

ㅤㅤ

✵Solution:-

$\boxed{ \frak{Area \: of \: rectangle =length ×breadth }}$

$\bf{ \pink{Area \: of \: ABCD = 40×30=1200m²}}$

A.T.Q

A path of 5 meter runs inside the park

Let EFGH be inner rectangular park excluding the path

$\sf \: |Length \: EF = 40-10=30 meters. |$

$\sf \: | Breadth \: EF=30-10=20 meters |$

$\underline{ \boxed{ \sf{Area \: of \: PQRS = 30×20=600m²}}}$

Hence,

Area of path = Area of ABCD -Area of EFGH

$\boxed{ \underbrace{ \sf \: Area= 1200- 600m²}}$

Therefore the area of path is 600 m²

╼╼╼╼╼╼╼╼╼╼╼╼╼╼╼╼╼╼╼╼╼╼╼

$\: \: \: \: \: \: \: ⠀\large {\boxed{\sf{\mid{\overline {\underline{ \color{maroon}{ {\star More\:To\:know\::}}}\mid}}}}}$

$⠀\begin{gathered}\boxed{\begin {array}{cc}\\ \large \red\dag\quad \Large\underline{\bf{ \color{aqua}{ Formulas\:of\:Areas:-}}}\\ \\ \red\star\sf Square=(side)^2\\ \\ \pink\star\sf Rectangle=Length\times Breadth \\\\ \blue\star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \orange \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \green\star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$