Question

A rectangular park is 45m long and 30m wide. A path 2m wide is constructed outside the park. Find the cost cementing the path at the rate of ₹ 20 per m². plz tell ans fast guys plz ​

Answer 1

Given:

$\sf{\rightarrow length\:of\:the\:rectangular\:park\:= 45m}$

$\sf{\rightarrow breadth\:of\:the\:rectangular\:park\: = 30m}$

$\sf{\rightarrow width\:of\:the\:path\:constructed\: outside\:the\:park\:= 2m}$

To Find:

cost of cementing the path at the rate of rupees 20 per m²

Solution:

$\sf{Let\:"ABCD"\:be\:the\:rectangular\: park}$

therefore,

• $\sf\red{ AB = DC = 45m}$

• $\sf\red{ AD = BC = 30m}$

$\sf{Let\:"EFGH"\:be\:the\:path\:that\:is\: constructed\:outside\:the\:park}$

therefore,

• $\sf\purple{ EF = GH = 45 + (2+2) = 49}$

• $\sf\purple{EH = FG = 30 + (2+2) = 34}$

Now,

to find the cost of cementing the path,first we need to find the area of the path

So,

$\sf{area\:of\:rectangle\:ABCD\:= 45 × 30 = 1,350m^2}$

$\sf{area\:of\:rectangle\:EFGH\:= 49 × 34 = 1,666m^2}$

Therefore,

${\boxed{\orange{\sf{area\:of\:the\:path = rectangle\:EFGH\:-\:rectangle\:ABCD}}}}$

$\sf{\implies area\:of\:the\:path\:= 1,666 - 1,350}$

$\sf{\implies area\:of\:the\:path\:= 316m^2}$

Now,

$\sf{cost\:of\:cementing\:the\:path\:per\: metre\:= 20}$

$\sf{cost\:of\:cementing\:the\:path\:for\: 316m\:= 20 × 316}$

$\sf{cost\:of\:cementing\:the\:path\:= 6,320}$

Hence,

cost of cementing the path for 316m² is 6,320

★ $\bf\underline\color{purple}{NOTE}$: kindly swipe left to see the answer clearly ♡ :)