Question

A rectangular park is 46 m long and 31 m wide.A path 2 m wide is constructed outside the park. Find the area of the path​

Answer 1

Answer:

original length =46m.

original breath =31m.

length and width of path =2m.

length including path =46+2=48m.

width including path =31+2=33m.

area of rectangle =L * B.

=48*33

=1784m².

Answer 2

Answer:

Step-by-step explanation:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 46m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 31m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Length of the rectangular park = 46m

Breadth of the rectangular park = 31m

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,0){\framebox(5.5,2.5)}\put(0.5,0.5){\framebox(4.5,1.5)}2m\end{picture}$

When a path 2m wide is constructed outside,

Breadth becomes , 31 + 2 × 2 = 35m.

Length also becomes , 46+4 = 50m.

Area of the path = Area of Smaller rectangle - Area of bigger rectangle

Area of Smaller Rectangle

l = 46m

b = 31m

Area of the rectangle = 46 × 31

Area = 1426m²

Area of Larger Rectangle

l = 50m

b = 35m

Area of the rectangle = l×b

Area of the rectangle = 50 × 35

Area = 1750m²

Area of The Path

Area of path =  Area of larger rectangle - Area of smaller rectangle

Area of the path = 1750 - 1426

Area of the path = 324m²