A rectangular park is 50 m long and 35 m broad a 3.5 broad pavement runs along the boundry of the park find the cost of cementing this pavement at the rate of 400 per 8m2
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₹32200 is the cost for cementing
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Area of rectangular park=length x breadth=50 x 35=1750
length of outer boundary=50+2x 3.5=50+7=57
breadth of outer boundary=35+2 x 3.5=35+7=42
area of outer rectangle=legthxbreadth=57x42=2394
area of pavement =are of outer rectangle-area of inner rectangle=2394-1750=644
cost of cementing=644/8x400=rs.32200
length of outer boundary=50+2x 3.5=50+7=57
breadth of outer boundary=35+2 x 3.5=35+7=42
area of outer rectangle=legthxbreadth=57x42=2394
area of pavement =are of outer rectangle-area of inner rectangle=2394-1750=644
cost of cementing=644/8x400=rs.32200
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