Question

A rectangular park is 50 m long and 35 m broad. A 3.5 m broad pavement runs along the boundary of the park. Find the cost of cementing this pavement at the rate of `400 per 8 m2. Give the answer typed.

Answer 1

Given:-

• Length of Rectangular Park = 50m

• Breadth of Rectangular Park = 35m

• A 3.5m Board Pavement running along the boundary of the Park.

To Find:-

• The Cost of Cementing the Pavement at the rate of 400per 8m²

Formulae used:-

• Area of Rectangle = Length × Breadth.

How To Solve?

• For solving this, we have to find the Area of Pavement

• To Find the area of Pavement first we have to find the Area of Rectanglular park excluding the Pavement and area of Rectanglular park including the Pavement.

• after that we will subtract the both and find the area of Pavement.

Let's Begin!

Now,

→ Length of Rectangle = 50

→ Breadth of Rectangle = 35

→ Area of Park excluding Pavement =50× 35 = 1750m²

Hence, The area of Park is 1750m².

Now, After including the Pavement we get,

→ Length of Park = 50 + 3.5 + 3.5 → 57

→ Breadth of Park = 35 + 3.5 + 3.5 → 42

→ Area of Park including Pavement = 57 × 42= 2394m²

Therefore,

→ Area of Pavement = Area of Park including Pavement - Area of Park excluding Pavement

→ Area of Pavement = 2394m² - 1750→ 644m²

Now,

→ Cost of cementing Pavement Per 8m² = 400rupees.

→ Cost of cementing 644m² = 644/8 × 400

→ Cost of cementing = 80.5 × 400 → 32200.

Hence, The cost of Painting the Pavement is 32200rupees.

Answer 2

${\huge{\purple{\underline{\underline{\bf{\pink{\mathfrak{Question}}}}}}}}$

• A rectangular park is 50 m long and 35 m broad. A 3.5 m broad pavement runs along the boundary of the park. Find the cost of cementing this pavement at the rate of `400 per 8 m2. Give the answer typed.

${\huge{\purple{\underline{\underline{\bf{\pink{\mathfrak{Answer}}}}}}}}$

${\huge{\purple{\underline</strong><strong>{</strong><strong>\</strong><strong>boxed</strong><strong>{\underline{\bf{\</strong><strong>green</strong><strong>{\mathfrak{</strong><strong>Given</strong><strong>:</strong><strong>-</strong><strong>}}}}</strong><strong>}</strong><strong>}}}}$

• Length of Rectangular Park = 50m

• Breadth of Rectangular Park = 35m

A 3.5m Board Pavement running along the boundary of the Park.

${\huge{\purple{\underline{\boxed{\underline{\bf{\green{\mathfrak{To\: find}}}}}}}}}$

The Cost of Cementing the Pavement at the rate of 400per 8m²

${\huge{\purple{\underline{\boxed{\underline{\bf{\green{\mathfrak{Formulae\: used}}}}}}}}}$

• Area of Rectangle = Length × Breadth.

Now,

• → Length of Rectangle = 50

• → Breadth of Rectangle = 35

• → Area of Park excluding Pavement =50× 35 = 1750m²

Hence, The area of Park is 1750m².

Now, After including the Pavement we get,

• → Length of Park = 50 + 3.5 + 3.5 → 57

• → Breadth of Park = 35 + 3.5 + 3.5 → 42

• → Area of Park including Pavement = 57 × 42= 2394m²

Therefore,

• → Area of Pavement = Area of Park including Pavement - Area of Park excluding Pavement

• → Area of Pavement = 2394m² - 1750→ 644m²

Now,

• → Cost of cementing Pavement Per 8m² = 400rupees.

• → Cost of cementing 644m² = 644/8 × 400

• → Cost of cementing = 80.5 × 400 → 32200.

Hence, The cost of Painting the Pavement is 32200rupees.