a rectangular park is 50m long and 35m broad. A 3.5m broad pavement runs along the boundary of the park. Find the cost of cementing this pavement at the rate of ₹400 per 8m²
Answers
Answer:
answer is 32200
Step-by-step explanation:
Area of the pavement = Area of the rectangle formed after making pavement−area of the original rectangle.
=LB−lb
=50+3.5×2×(35+3.5×2)−50×35
=2394−1750=644m2
Threrefore cost of cementing this pavement =644×8400=Rs.32200
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Answer:
Rs. 27300
Step-by-step explanation:
So, there is a pavement around the boundary of park. The breadth of pavement is 3.5m,
Name the rectangles as ABCD and EFGH. The width of pavement is 3.5 everywhere. Produce or extend the lines of EFGH onto ABCD and name the points as I,J,K,L respectively.
In rectangle LICD, length = 50 , breadth = 3.5. Area = 50*3.5 = 175 sq.m
Rectangle LICD and ABJK are equal or congruent. So area of ABJK is also 175m.
now consider rectangle KEHL. Here, HE will be 35 - (3.5+3.5) = 35-7 = 28.
So, length in this is 28m. breadth is 3.5m
Area of rectangle KEHL = 28*3.5 = 98 sq.m
Rectangle GIJF and rectangle KEHL are equal. So areas of both are 98 sq.m
Total area of pavement = 175+175+98+98 = 546m²
Now, rate for cementing 8m² = 400. for 1m², it is 50 rs.
So, for 546m², the cost will be 546*50 = Rs. 27300
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