Question

A rectangular park is 60 m long and 40 m wide . A path 2.5 m wide is constructed outside the park . Find the area of the path​

Answer 1

Answer:

Length of inner rectangle- 60m

Breadth of inner rectangle-40m

area of inner rectangle =60×40

= 2400 m2

length of outer rectangle=60+(2 .5×2)

=65

breadth of outer rectangle= 40+(2.5×2)

=45

area of outer rectangle = 65 × 45

=2925m2

Length of path = (outer area - inner area)

=(2925-2400)

= 525m2

So area of path is 525m2

Answer 2

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A rectangular park is 60 m long and 40 m wide . A path 2.5 m wide is constructed outside the park . Find the area of the path...

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$length \: = \: 60m. \\ breadth \: = \: 40m.$

$A \: path \: 2.5 \: m \: wide \: is \: constructed \: outside \: the \: park \:$

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$Length\:Of\:Park\:=60m$

$Breadth\:Of\:Park\:=40m$

$Area\:=2440m$

$Path\:=2.5m$

$= 40 + 2.5 \times 60 + 2.5 \\ = 42.5 \times 62.5 \\ = 2656.25 \\ = 2656 - 2400 \\ = 256.25$

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