A rectangular park is 65 m long and 30 m
wide. A path 2.5 m wide is constructed
all along inside the park. Find the area
of the path.
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3
Answer:
Area of the rectangle = Length×Breadth=65×50=3250m2
Given Width of the Path = 2m
Length of the Path is Parellel to the side , Hence Length = 65 m
Area of the Path 1 = Length×Width=65×2=130m2
Given Breadth of the Path = 2m
Length of the Path2 is Parellel to the other side , Hence Length = 50 m
Area of the Path2 = Length×Breadth=50×2=100m2
Add Both the Area of the Path = 130+100=230m2
Area of the Common Field ABCD = 2×2=4m2
As both path are overlapping each other, so to calculate the area of shaded portion area of one square should be deducted from the area of the total path.
∴ Total Area for the Path Construction = 230−4=226m2
∴ Cost of Constructing the Path = 230−4=226×69=15594
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